scala - Removing nodes from XML -

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i want produce xml document another, filtering subnodes match specified criterion. how should that?

you can use ruletransformer scala.xml.transform.

suppose have action attribute "remove" value

  val removeit = new rewriterule {     override def transform(n: node): nodeseq = n match {       case e: elem if (e \ "@action").text == "remove" => nodeseq.empty       case n => n     }   }  new ruletransformer(removeit).transform(yourxml)

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