sql - How to get rightmost 10 places of a string in oracle -

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i trying fetch id oracle table. it's tn0001234567890345. want sort values according right 10 positions (e.g. 4567890345). using oracle 11g. there function cut rightmost 10 places in oracle sql ?

thanks in advance

tismon

you can use substr function as:

select substr('tn0001234567890345',-10) dual;

output:

4567890345

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