python - deleting rows in numpy array -

i have array might this:

anovainputmatrixvaluesarray = [[ 0.96488889, 0.73641667, 0.67521429, 0.592875,  0.53172222], [ 0.78008333, 0.5938125, 0.481, 0.39883333, 0.]] 

notice 1 of rows has 0 value @ end. want delete row contains zero, while keeping row contains non-zero values in cells.

but array have different numbers of rows every time populated, , zeros located in different rows each time.

i number of non-zero elements in each row following line of code:

numnonzeroelementsinrows    = (anovainputmatrixvaluesarray != 0).sum(1) 

for array above, numnonzeroelementsinrows contains: [5 4]

the 5 indicates possible values in row 0 nonzero, while 4 indicates 1 of possible values in row 1 zero.

therefore, trying use following lines of code find , delete rows contain 0 values.

for q in range(len(numnonzeroelementsinrows)):     if numnonzeroelementsinrows[q] < numnonzeroelementsinrows.max():         p.delete(anovainputmatrixvaluesarray, q, axis=0) 

but reason, code not seem anything, though doing lot of print commands indicates of variables seem populating correctly leading code.

there must easy way "delete row contains 0 value."

can show me code write accomplish this?

the simplest way delete rows , columns arrays numpy.delete method.

suppose have following array x:

x = array([[1,2,3],         [4,5,6],         [7,8,9]]) 

to delete first row, this:

x = numpy.delete(x, (0), axis=0) 

to delete third column, this:

x = numpy.delete(x,(2), axis=1) 

so find indices of rows have 0 in them, put them in list or tuple , pass second argument of function.