Macro in a loop? -

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for(x;x<crap;x++) {     macro(x,y); }

how handled preprocessor? loop unrolled or else?

the macro expanded before code compiled - doesn't matter whether it's in loop or anywhere else.

#define macro(x, y) dosomething(x, y) for(x;x<crap;x++){     macro(x,y); }

will expand to:

for(x;x<crap;x++){     dosomething(x,y); }

the context surrounding macro(x,y) has no effect on how preprocessor expands it.

(the preprocessor doesn't know programming language you're using - c, python, brainfuck or letter bank manager , expand macros same way.)


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