linux - Parse folder name in bash -

i have folders naming convention:

yearmonthday_jobcode_descriptor

ie 20101007_gr1234_whatsit

i'm attempting write script few things:

here current loop, can see bash scripting pretty mediocre.

#!/bin/bash  file in $1/*;    if [ -d $file ];         echo $(echo $file | grep -oe "[0-9]{8}_[a-z]*[0-9]*_?.*")    fi done

i can handle looping, main concern @ moment how extract folder names variables can compared dates. current regex above checks conformity convention.

you can use cut command tokenize string (-d specifies delimiter, -f specifies field want keep) -

echo 20101007_gr1234_whatsit | cut -d'_' -f1

gives

20101007

from there, can use date command parse date-

foo=`date -d 20101007 +%s`

will convert date string epoch time (seconds since jan 1, 1970) can compared.

if don't want mess epoch time, can call date multiple times parse different parts -

 day=`date -d 20101007 +%d`  month=`date -d 20101007 +%m`  year=`date -d 20101007 +%y`

but make comparisons little more complicated.

ERT